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If the velocity ratio for an open belt drive is 8 and the speed of driving pulley is 800 r.p.m, then considering an elastic creep of 2% the speed of the driven pulley isĬlarification: Velocity Ratio = Velocity of belt on driver/Velocity of belt on driven Recesses in the smaller wheel, n 2 = 9/10 x 10 = 9 If the efficiency of the machine is 50%, find the load lifted by an effort of 300N.Ĭlarification: Let the recesses in the larger wheel, n 1 = 10 In a weston differential pulley block, the number of recesses in the smaller wheel is 9/10 of that of the larger wheel. What is the efficiency of the system at 2kN?Įfficiency at this load = effort without friction/effort with frictionĦ. Further wastage in friction increases the pull at the rate of 3% of the load lifted. When not loadwd the effort required to raise the movable block is 35N. Five pulleys are arranged in the second system of pulleys. When the system is considered frictionless nP = Wĥ. What is the effort required to raise a load of 2kN?įrictional effort at 2 kN loading = 35 + 2000 x 3/100 = 95 N When not loaded the effort required to raise the movable block is 35N. Let the pull exerted by the man be P newton.ĭue to this pull the effective load on the lower platform will reduce to (700 – P)Ĥ. Weight of the lower block and platform = 100 N Neglecting friction, the minimum pull of the man will beĬlarification: n = total number of pulleys in the system = 5
MOVABLE PULLEY FREE
The man himself supports by exerting a downward pull at the free end of the rope. The platform and the lower block weigh 100N.
![movable pulley movable pulley](https://hi-static.z-dn.net/files/d34/4373388408f494f416bb04ddec8fc22a.jpg)
A person weighing 600 N platform attached to the lower block of a system of 5 pulleys arranged in the second system. If the weight of each pulley is 5 N, calculate the effort which can lift a load of 10 kN.Ĭlarification: We know that M.A. Four movable pulleys are arranged as in the first system. Let W = load which can be lifted by the machineĢ.
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Find the load which can be lifted by an effort of 100 N, assuming an efficiency of the machine to be 75%.Ĭlarification: Diameter of effort wheel, D = 400 mmĭiameter of longer axle, d 1 = 2 x 150 = 300 mmĭiameter of the smaller axle, d 2 = 2 x 100 = 200 mm The radii of the load axles are 150mm and 100 mm respectively. In a wheel and differential axle, the diameter of the effort wheel is 400 mm. Machine Kinematics Multiple Choice Questions on “Pulleys”.ġ.